· Purpose
The purpose
of sieve analysis is commonly used to figure out the particle size distribution
of unsaturated soil sample. The relative proportions of different grain sizes
is very important for soil. Soil can be lead to failure or is able to carry it
function due to size distribution.
· Standard
Sieve
analysis procedure follow by ASTM D 422 – Standard Test Method of Particle size
Analysis of soil.
2. Apparatus
- Set of sieves
- Sieve Shaker
- Balance
- Cleaning Brush
- Pan
3. Test
Procedure
1. We need to make the soil sample becomes unsaturated by
placing in the oven for 24 hour.
2. Then, we take representative soil sample from oven for
our sieve analysis.
3. Using balance and record the weight of dry soil sample.
In this experiment we take 800g of soil sample.
4. Record the weight of each sieve as well as the bottom
pan to be used in the analysis.
5. Each sieves have to be clean.
6. Pour the 800g soil sample into set of sieves. Set of
sieves has to be arrange from top which has larger to smaller diameter size at
bottom. Also, we place a pan to collect fined grain soil that go pass through
smallest sieve (#200).
7. Activate sieve shaker machine with 10 minutes time
limit. Make sure we place and tighten a belt to the set to sieves to avoid any accident occur
unintentionally during shaking time.
8. Record the weight of each
sieve with its retained soil.
9. Weight the bottom pan.
4. Data
Analysis and Calculation
Mass
Retained (gr)
In order to obtain mass retained soil we take the weight of soil
retained on each sieve subtracting with the weight of empty sieve.
Mass Retained (gr) = Weight of soil on each sieves –
Weight of each empty sieves
Sieve Number
|
Weigh of Sieves
|
Weight of sieves + soil retained
|
Mass Retained (gr)
|
4
|
382
|
399
|
17
|
10
|
333
|
423
|
90
|
20
|
331
|
562
|
231
|
40
|
320
|
512
|
192
|
80
|
316
|
526
|
210
|
100
|
321
|
349
|
28
|
200
|
309
|
334
|
25
|
Pan
|
239
|
245
|
6
|
Mass Dry Soil
|
800g
|
%
Retained
In
order to obtain % retained soil we take the weight mass retained in each sieves
divide by sum of total mass retained then multiply by 100%.
|
In order to obtain % Finer soil we substance 100% with
each sieves .
|
% Finer = 100% - each sieves
Data Analysis
Sieve Number
|
Opening (mm)
|
Mass Retained (gr)
|
% Retained
|
|
% Finer
|
||
4
|
4.75
|
17
|
2.13
|
2.13
|
97.88
|
||
10
|
2
|
90
|
11.25
|
13.38
|
86.63
|
||
20
|
0.85
|
231
|
28.88
|
42.25
|
57.75
|
||
40
|
0.425
|
192
|
24.00
|
66.25
|
33.75
|
||
80
|
0.18
|
210
|
26.25
|
92.50
|
7.50
|
||
100
|
0.15
|
28
|
3.50
|
96.00
|
4.00
|
||
200
|
0.075
|
25
|
3.13
|
99.13
|
0.88
|
||
Pan
|
6
|
0.75
|
99.88
|
0.13
|
|||
Dry Soil
|
800g
|
5. Conclusion
According to value of Cu and
Cc from calculation above, we can identify the soil clearly whether it is
classified in well graded, poorly graded or gap graded soils. Cu value 4.5
which is higher than 4 indicate a wider assortment of particle size. A soil
that has uniformity coefficient of >4 is described as a well graded soil. In
addition, the value of coefficient of curvature is 0.5 which is <1 which
indicate gap graded soil.
--------------------------------------------------------------------------------
Reference: www.uta.edu/ce/geotech/lab/Main/sieve/index.htm
Author: Nararoth Theng
Publish date: 29 March 2015
Phnom Penh, Cambodia
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